What is yhe heat, q, required to melt 10 grams of ice in a) Joules b) calories?

Answer 1

Ice has a latent heat of fusion of 79.8 cal/g or 334 J/g

q = m∆H_fus = 10 g x 79.8 cal/g = 798 cal

q = m∆H_fus = 10 g x 334 J/g = 3340 J