A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 22 grams. The heaviest 10% of fruits weigh more than how many grams?

Answer 1

Draw a normal distribution curve. We want the heaviest 10%. Thus mark off some weight on the normal distribution curve. The area to the right of this weight is equal to 10%.

Figure out the z-score that gives you an area of 10% to the right of it.

Change this z-score back into x (The weight of the fruit) using the equation z = (x - µ)/ σ