J.R. S. answered 10/07/21
Ph.D. University Professor with 10+ years Tutoring Experience
(a) Since we don't see the figures (3 and 4) we can't tell which arm is higher so we'll assume that the pressure increased so the new pressure would be 758 torr + 144 torr = 902 torr (note: 1 mm Hg = 1 torr)
(b) 902 torr x 1 atm/760 torr = 1.19 atm
(c) 1.19 atm x 101.325 kPa/atm = 121 kPa