What is the partial pressure of SO2Cl2 in this mixture?

Question

Consider the reaction:

SO2Cl2(g)⇌SO2(g)+Cl2(g),

Kp=2.91×103 at 298 K

In a reaction at equilibrium, the partial pressure of SO2 is 0.145 torr and that of Cl2 is 0.337 torr .

Answer 1

As was the case with your previous question...

Kp = (SO₂)(Cl₂) / (SO₂Cl₂)

2.91x10³ = (0.145)(0.337) / (SO₂Cl₂)

(SO₂Cl₂) = 1.42x10^-4 torr