What is the partial pressure of NOBr in this mixture?

Question

Consider the reaction                   

2NO(g)+Br2(g)⇌2NOBr(g)              ,

Kp=28.4 at 298 K

 In a reaction mixture at equilibrium, the partial pressure of NO is 104 torr and that of Br2 is 135 torr .

Answer 1

2NO(g) + Br₂(g) ⇌ 2NOBr(g)

Kp = (NOBr)² / (NO)²(Br₂)

28.4 = (x)² / (104)²(135)

x = 6440 torr