J.R. S. answered 10/06/21
Ph.D. University Professor with 10+ years Tutoring Experience
0.88 grams = 880 mg (0.88 g x 1000 mg/g = 880 mg)
880 mg / 1000 mg (x100%) = 88%
% error = 100 - 88 = 12%
Gift D.
asked 10/06/21After completing an experiment, a student extracts a sample of calcium carbonate with a mass of 0.88 grams from an antacid tablet that claims to have 1000 mg of calcium carbonate. What is the percent error in this student's experiment? Round your answer to two decimal places.
J.R. S. answered 10/06/21
Ph.D. University Professor with 10+ years Tutoring Experience
0.88 grams = 880 mg (0.88 g x 1000 mg/g = 880 mg)
880 mg / 1000 mg (x100%) = 88%
% error = 100 - 88 = 12%
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