Write the equation of a line perpendicular to the line y = 2x - 3 that goes through the point (4,3).

Answer 1

The line y = 2x - 3 has a slope of 2 and a y-intercept of -3. A perpendicular line's slope is the negative reciprocal of 2, so it's -1/2. Using the point-slope form, where m = -1/2 and (x₁,y₁) = (4,3):

y - y₁ = m·(x -x₁)

y - 3 = (-1/2)·(x - 4)

Solve for y to get the equation in slope-intercept form (y = mx+b)