J.R. S. answered 10/05/21
Ph.D. University Professor with 10+ years Tutoring Experience
Zn(ClO4)2(aq) + K2CO3(aq)⟶ZnCO3(s) + 2KClO4(aq)
Since a precipitate (s) is formed, those are the only ions that need to be considered in the net ionic equation as all others are soluble.
NIE: Zn2+(aq) + CO32-(aq) ==> ZnCO3(s)