How many particles of calcium bromide will be needed to produce 2.2 moles of the metal hydroxide as based on the reaction?

Question

Reaction:

2NaOH(aq) + CaBr2(aq) ==> Ca(OH)2 + 2NaBr(aq)

Answer 1

From the stoichiometry of the balanced equation, we find moles of CaBr₂ needed to produce 2.2 moles of Ca(OH)₂.

2.2 mol Cu(OH)₂ x 1 mol CaBr₂ / 1 mol Ca(OH)₂ = 2.2 mols CaBr₂ needed

Using Avogadro's number, we convert mols CaBr₂ to particles (molecules/formula units) of CaBr₂.

2.2 mols CaBr₂ x 6.022x10²³ particles / mol = 1.3x10²⁴ particles