Find the intersection

Question

y = -x^2 and y = x2 - 2x - 2

Answer 1

3x^2 - 2x - 2 = 0

x = 2/6 + or - (1/6)sqr(4+4(3)2)) = 1/3 + or - sqr28/6 = about 1.215 or -0.55 (ignore the negative "solution")

y= -x^2 = -.3 or about 1.5 (ignore -.3)

intersection point is about (1.2, 1.5)