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Trigonometry hardest questions

 x^2/a^2 + y^2/b^2 = 2
know have to squar them... but really confused....
pleasee help mee...????

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Alex S. | Retired, Looking to Share My Love of Mathematics and ComputersRetired, Looking to Share My Love of Mat...
4.8 4.8 (75 lesson ratings) (75)

Not clear on what you are asking?!  The equation fits into the general formula for an ellipse,

(x-h)2/a2 + (y-k)2/b= 1

The length of the "major" (longer) axis of symmetry is "a"; the length of the "minor" (shorter) axis is "b"; there are two vertices and two co-vertices.  You can find all the details at

You can fit your formula into the general equation by dividing both sides by 2.

Kevin S. |
5.0 5.0 (4 lesson ratings) (4)

Square each to get x2/a2 cos2 Θ + xy/ab cos Θ sin Θ + y2/b2 sin 2 Θ = 1 and 
x2/a2 sin2 Θ - xy/ab cos Θ sin Θ + y2/b2 cos 2 Θ = 1. Now add them together - note that

1 - your center terms drop out 

2 - factor common terms and you will be left with
x2/a2 (cos2 Θ + sin 2Θ) + y2/b2 (cos2 Θ + sin 2Θ) = 2

3 - What does (cos2 Θ + sin 2Θ) equal? Replace it and solve.

Good luck. 




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