Calculate the energy, in joules, to heat a cube of gold with a volume of 8.00 cm3 from 15 ∘C to 27 ∘C. (Assume that the density of gold is 19.3 g/cm3, the specific heat for gold is 0.129 J/g∘C.)

Answer 1

1) find the mass of the cube of gold:

8.00 cm3 x 19.3 g / cm3 = 154.4 g

2) use q = mC∆T to find the energy in joules:

q = heat energy = ?

m = mass = 154.4 g

C = specific heat = 0.129 J/gº

∆T = change in temperature = 27º - 15º = 12º

q = (154.4 g)(0.129 J/gº)(12º)

q = 239 Joules