J.R. S. answered 09/27/21
Ph.D. University Professor with 10+ years Tutoring Experience
4NH3(g) + 5O2(g)⟶ 4NO(g) + 6H2O(g) ... balanced equation
(1) Find the limiting reactant (moles of each / coefficient in balanced equation)
70.3 g NH3 x 1 mol NH3 / 17 g = 4.14 mols NH3 (÷4 ->1.030
70.3 g O2 x 1 mol O2 / 32 g = 2.20 mols (÷5 ->0.44)
O2 is limiting
Theoretical yield of H2O:
2.20 mols O2 x 6 mols H2O / 5 mols O2 x 18 g / mol H2O = 47.5 g H2O