A 925 mL NaCl solution is diluted to a volume of 1.28 L and a concentration of 8.00 mol L−1 . What was the initial concentration?

Question

Express the molar concentration numerically.

Answer 1

We can use V1M1 = V2M2 to solve this problem.

V1 = initial volume = 925 ml = 0.925 L

M1 = initial concentration = ?

V2 = final volume = 1.28 L

M2 = final concentration = 8.00 M

Solving for M1, we have...

M1 = V2M2 / V1 = (1.28 L)(8.00 M) /0.925 L

M1 = 11.1 M