Perimeter of a triangle 0,9 and 0,1 and 4,9

Answer 1

(0,9) (0,1) and (4,9) are 3 vertices of a right triangle

with sides 8, 4 and sqr(64+16) = sqr80=4sqr5

the perimeter = 8+4+4sqr5 = 12+4sqr5 = about 12+4(2.2) = 12+8.8 = 20.8

top of the right triangle has length 4, the distance from (0,9) to (4,9) = 4-0=4

left side of the right triangle has length 8, the distance from (0,1) to (0,9) = 9-1

the hypotenuse of the right triangle = square root of 8^2 + 4^2 = sqr(64+16) = sqr80 = 4sqr5