If the frequency factor is 1.2×10^13s−1, what is the activation barrier?

Question

The rate constant of a reaction at 32  was measured to be 5.2×10⁻²  .

Answer 1

Solve the Arrhenius equation for Ea:

k = Ae^-Ea/RT

ln k = -Ea/RT + ln A

R = 0.008314 kJ/Kmol

T = temperature in K = 32 + 273 = 302K

ln 5.2x10^-2 = -Ea/(0.008314)(305) + ln 1.2x10¹³

-2.96 = -Ea / 2.964 + 30.12

-Ea = -98.05

Ea = 98.05 kJ/mol