What is an equation of the line that passes through the point (-2,-4)and is parallel to the line x-2y=6

Answer 1

By transforming x-2y = 6 into y = 1/2(x) - 3

m = 1/2

Using the equation y = mx+b

y = (1/2)x+b

Plugging in points:

-4 = (1/2)(-2)+b

b = -3

Resulting eq. through (-2,-4) and parallel is y = (1/2)x - 3

Answer 2

What is an equation of the line that passes through the point (-2,-4)and is parallel to the line x-2y=6

Parallel lines have the same slope.

For the equation of a line in Standard Form (Ax+By=C), the slope is (-B/A). The line you want has an equation that looks like x-2y = C.

Put in the values of x and y from the point to calculate C.

-2-2(-4) = C

6 = C

The line is:

x-2y = 6

Check:

Is -2 -2(-4) = 6 ?

-2 + 8 = 6 ?

6 = 6? yes