How many grams of NH3 are needed to provide the same number number of molecules as in 0.95 g of SF6

Question

How many grams of NH3 are needed to provide the same number number of molecules as in 0.95 g of SF6?

Answer 1

So, first we need to find the number of molecules in 0.95 g of SF₆.

molar mass SF₆ = 146 g / mol

0.95 g SF₆ x 1 mol/146 g x 6.022x10²³ molecules/mol = 3.9x10²¹molecules SF₆

Now we can find the mass (g) of NH₃ needed to produce 3.9x10²¹ molecules:

molar mass NH₃ = 17 g/mol

3.9x10²¹ molecules NH₃ x 1 mol NH₃ / 6.022x10²³ molecules x 17 g NH₃/ mol = 0.11 g NH₃