To find the score that respresents the 75th percentile you need to refer to a normal table and find the z score that represents a probability of 0.7500. The appropriate z score is 0.675. To find the actual SAT score, use the following formula X = Zσ+μ, where σ is the standard deviation and μ is the mean for SAT scores
X = 0.675 * 198 + 1101 = 1235 rounded to the nearest whole number would be the 75th percentile.
To find the equivalent ACT score, use the ACT standard deviation and mean
X = 0.675 * 3.9 + 19.2 = 21.8
If a student scores 1407 on the SAT, we need to find the standardized score (z score) for 1407
z = (X-μ)/σ = (1407-1101)/198 = 1.545
The equivalent ACT score is found by using the formula from the first 2 parts of this question using 1.545 as the z score
X = 1.545 * 3.9 + 19.2 = 25.5
Please note, your answers may differ a bit based on how you are obtaining your z-scores from the normal table? Are you using the z-score whose probability is closest to .75 or are you interpolating? Instead of using a table, are you using a calculator or some statistical package and how many decimal places are you using?