The reaction below has a Kp value of 59.6. What is the value of Kc for this reaction at 462 K?

Question

N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)

Answer 1

Kp = Kc(RT)∆n

Kp = 59.6

Kc = ?

R = 0.0821 Latm/Kmol

T = temperature in K = 462K

∆n = change in number of moles of gas = 2 - 4 = -2

59.6 = Kc(0.0821 * 462)^-2 = 0.000695Kc

Kc = 8.6x10⁴