General Chemistry I HW

Question

How many moles of CaCO₃ are there in an antacid tablet containing 0.500 g CaCO₃? 

_______ mol CaCO3

How many formula units of CaCO₃ are in this tablet?

_______ formula units

Answer 1

molar mass CaCO₃ = 100.1 g/mol

0.500 g CaCO₃ x 1 mol / 100.1 g = 0.00500 moles CaCO₃ (3 sig. figs.)

0.005 moles CaCO₃ x 6.022x10²³ form.units / mole = 3.01x10²¹ formula units (3 sig. figs.)

Answer 2

0.00568 moles CaCo3

3.42 x 10(21) Formula units