
Bobosharif S. answered 09/18/21
Mathematics/Statistics Tutor
f(x)= 1/x-4 , g(x)= 1/6-x
f+g= 1/x-4+1/6-x =1/x-x +1/16-4 = 1/x-x-63/16
Domain of f+g is x≠0
x∈(-∞, 0) ∪(0, ∞)
Similar for f-g
fg
= (1/x-4)(1/6-x)=1/(6x)+4x-5/3.. Here Domain D(fg)=is the same as before: = (-∞, 0) ∪(0, ∞)
f/g
= (6(1-4x)/(x(1-6x)), So the domain is
(-∞, 0) ∪(0,1/6) ∪(1/6, ∞)