Write the first trigonometric function in terms of the second for 𝜃 in the given quadrant. tan(𝜃), cos(𝜃); 𝜃 in Quadrant II

Answer 1

cos²θ + sin²θ = 1

So, sinθ = ±√(1 - cos²θ)

In quadrant 2, sinθ > 0, so sinθ = √(1 - cos²θ)

Therefore, tanθ = sinθ / cosθ = √(1 - cos²θ) / cosθ