calculate how many grams of Cr (OH) 3 are formed when 19 kg of KOH reacts with CrCl3

Question

calculate how many grams of Cr (OH) 3 are formed when 19 kg of KOH reacts with CrCl3

Answer 1

Write the balanced equation:

3KOH + CrCl₃ ==> Cr(OH)₃ + 3KCl ... balanced equation

Assuming the CrCl₃ isn't limiting:

19 kg KOH x 1000 g/kg x 1 mol KOH/56.1 g x 1 mol Cr(OH)₃ / 3 mol KOH x 103.1 g Cr(OH)₃/mol = 11.66 kg

= 12 kg of Cr(OH)₃ would be formed