the two equal sides of an isosceles triangle are each 42 centimeters. If the base mesures 32 centimeters, find the height and the measure of the two equal angles

Answer 1

Height h = √42² - 16² = 2√377; sinθ = 2√377/42 = √377/21; θ = sin^-1(√377/21) = 67.61°