J.R. S. answered 09/13/21
Ph.D. University Professor with 10+ years Tutoring Experience
43.0 g glucose x 1 mol glucose / 180 g x 6 mols O2 / mol glucose x 32 g O2/mol = 45.9 g O2
Jaylin J.
asked 09/12/21Glucose, C6H12O6 is used as an energy source by the human body. The overall reaction in the body is described by the equation
C6H12+6O2-----> 6CO2+6H2O
Calculate the number of grams of oxygen required to convert 43.0g of glucose to CO2 and H2O
J.R. S. answered 09/13/21
Ph.D. University Professor with 10+ years Tutoring Experience
43.0 g glucose x 1 mol glucose / 180 g x 6 mols O2 / mol glucose x 32 g O2/mol = 45.9 g O2
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