J.R. S. answered 09/08/21
Ph.D. University Professor with 10+ years Tutoring Experience
Inspecting the data, we can see that at 10 seconds, the [A] is 1/2 of what it was initially, i.e. it went from 0.20 M to 0.10 M in 10 seconds. Thus, we can say the half time (or half life, t1/2) is 10 seconds. For a 1st order reaction, the fraction remaining at any time (t) is equal to 0.5 raised to the number of half lives elapsed. Written in mathematical form, we have...
fraction remaining = 0.5n
In this example, n = 4 half lives since 40 seconds represents 4 half lives.
fraction remaining = 0.54
fraction remaining = 0.0625
Thus, the concentration of A after 40 seconds would be 0.0625 x 0.20 M = 0.0125 M = 0.013 M