Mark M. answered 03/08/15
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
An alternative:
cos3x + sin3x = (1/2)(cos x + sin x)(2 - sin 2x)
= (1/2)(cos x + sin x)(2 - 2sin x cos x)
= (cosx + sin x)(1 - sin x cos x)
= cos x + sin x - sin x cos2x - sin2x cos x
= cos x - sin2x cosx + sin x - sin x cos2x
= cos x(1 - sin2x) + sin x(1 - cos2x)
= cos x (cos2x) + sin x (sin2x)
= cos3x + sin3x