This fits the requirements for using the binomial probability formula:
P(x successes in n tries) = n!/([x!(n-x)!) * p^x * (1-p) ^ (n-x)
where p is the probability of success (0.1) and n = sample size = 13
For example P(x = 5) = 13!/(5!8!) * 0.1^5 * 0.9*8
for 1) P(x >= 3) = 1 - P(x <= 2) = 1 - [ P(x = 0) + P(x = 1) + P(x = 2)]
2) P(x = 5 or x = 6) = P(x = 5) + P(x = 6)
3) P(x = 2)