
Mark M. answered 09/02/21
Mathematics Teacher - NCLB Highly Qualified
cot θ + tan θ
(cos θ / sin θ) + (sin θ / cosθ)
(cos2 θ + sin2 θ) / (sin θ cos θ)
1 / (sin θ cos θ)
(1 / sin θ)(1 / cos θ)
QED
Jon K.
asked 09/02/21Mark M. answered 09/02/21
Mathematics Teacher - NCLB Highly Qualified
cot θ + tan θ
(cos θ / sin θ) + (sin θ / cosθ)
(cos2 θ + sin2 θ) / (sin θ cos θ)
1 / (sin θ cos θ)
(1 / sin θ)(1 / cos θ)
QED
Mark M. answered 09/02/21
Retired Math prof with teaching and tutoring experience in trig.
cotθ + tanθ = cosθ / sinθ + sinθ / cosθ = (cos2θ + sin2θ) / (cosθsinθ) = 1 / (cosθsinθ)
= (1/cosθ) (1/sinθ) = secθ cscθ
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