No figure is shown. You need both the x and y coordinate. So, possibly your missing figure shows a unit circle. then the x coordinate would be 5/13
(5/13)^2 + (12/13)^2 = (25+144)/169 = 1
sint = 12/13
cost =5/13
tant = 5/12
cott = 12/5
sect =13/5
if t is in the 1st quadrant
it could also be in the 2nd quadrant, without further information or seeing P in the missing figure
in the 2nd quadrant
it's the same trig function values, except a couple sign changes
cost=-5/13
tant=-5/12
cott= -12/5
sint, cost and sect are the same in the 1st or 2nd quadrants
sint = opposite side over hypotenuse = y/r where y is the y coordinate of the point and r = 1 in a unit circle
cost = adjacent side over hypotenuse = x/r where x is the x coordinate of the point and r=1 on a unit circle
tant = y/x
cott = x/y
sect = r/y = 1/y
sint =y
cost =x
tant =y/x
cott =1/tant = x/y
sect = 1/sint = 1/y
the reference angle is a 5-12-13 right triangle, with hypotenuse =12, opposite side =12, adjacent side=5
13^2 = 12^2 + 5^2 but the adjacent side would = -5/12 in quadrant II
