sint = opposite side over hypotenuse = -3/7. hypotenuse = 7
cost = adjacent side over hypotenuse
adjacent side= -sqr(7^2 -3^2) = -sqr(49-9)= sqr40 = -2sqr10. take the negative square root because t is in quadrant III
cost = -2sqr10/7
Omar M.
asked 08/30/21Suppose that t is in the third quadrant and that sint = -3/7. What is the value of cost?
sint = opposite side over hypotenuse = -3/7. hypotenuse = 7
cost = adjacent side over hypotenuse
adjacent side= -sqr(7^2 -3^2) = -sqr(49-9)= sqr40 = -2sqr10. take the negative square root because t is in quadrant III
cost = -2sqr10/7
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