Inactive Tutor answered 08/30/21
Tutor
New to Wyzant
1 + tan^2 m = 1 / cos^2 m
tan^2 m = 1 / (-0.3)^2 - 1 = 91/9
tan m = sqrt(91/9) (positive for Q3)
Omar M.
asked 08/30/21Suppose that cosm=−3/10 and that m is in the third quadrant. What is the value of tanm?
Inactive Tutor answered 08/30/21
1 + tan^2 m = 1 / cos^2 m
tan^2 m = 1 / (-0.3)^2 - 1 = 91/9
tan m = sqrt(91/9) (positive for Q3)
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