
Michael M. answered 08/29/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
I'll go through some of these to give you a better understanding
Let's get fx for a).
We'll use the chain rule. The derivative of ln(x) is 1/x.
fx = 1/√(x2 + y2) • d/dx(√(x2 + y2))
Use the chain rule again. The derivative of √x is 1/(2√x)
fx = 1/√(x2 + y2) • 1/(2√x2 + y2) • d/dx(x2 + y2)
Use the chain rule again. The derivative of x2 + y2 with respect to x is 2x because y2 is seen as a constant.
Therefore,
fx = 1/√(x2 + y2) • 1/(2√x2 + y2) • 2x.
Let's get fy for b).
We have two functions multiplied both with y in them, so we'll have to use the product rule. If we were taking the derivative with respect to x, we wouldn't need the product rule because ln y would be seen as a constant.
Applying the product rule we get:
exy • d/dy(ln y) + (ln y) • d/dy (exy)
exy(1/y) + (ln y)(xexy)
Notice that the derivative of exy with respect to y is xexy because x is seen as a constant.
Ayse N.
Very nice and detailed explanation. Could you explain how we found option c for fx? I want to confirm my solution08/29/21