Help, I need help with this question quickly!!

Question

Ryan started his jog 30 minutes before Tiffany started. Ryan jogs at a constant speed of 4 miles per hour and Tiffany jogs at a constant speed of 6 miles per hour. How long will it take for Tiffany to catch up to Ryan?

Answer 1

d = r * t

d_Ryan = (t + 0.5)4

d_Tiffany = (t)6

4(t + 0.5) = 6t distances are equal.

4t + 2 = 6t

2 = 2t

1 = t

Answer 2

Hello Sarang.

The difference of their speed is 6-4 = 2 miles per hour;

In 30 min; Ryan had 0.5*4 = 2 miles (30 min = 0.5hour)

Since they have 2 miles apart and difference of their speed is 2mph

2/2 = 1 hour

hope that helps