Mark M. answered • 08/26/21

Mathematics Teacher - NCLB Highly Qualified

d = r * t

d_{Ryan} = (t + 0.5)4

d_{Tiffany} = (t)6

4(t + 0.5) = 6t distances are equal.

4t + 2 = 6t

2 = 2t

1 = t

Sarang B.

asked • 08/26/21Ryan started his jog 30 minutes before Tiffany started. Ryan jogs at a constant speed of 4 miles per hour and Tiffany jogs at a constant speed of 6 miles per hour. How long will it take for Tiffany to catch up to Ryan?

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Mark M. answered • 08/26/21

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Mathematics Teacher - NCLB Highly Qualified

d = r * t

d_{Ryan} = (t + 0.5)4

d_{Tiffany} = (t)6

4(t + 0.5) = 6t distances are equal.

4t + 2 = 6t

2 = 2t

1 = t

Hello Sarang.

The difference of their speed is 6-4 = 2 miles per hour;

In 30 min; Ryan had 0.5*4 = 2 miles (30 min = 0.5hour)

Since they have 2 miles apart and difference of their speed is 2mph

2/2 = 1 hour

hope that helps

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