The two equations are
y sinB = cos A Equation 1
x cosB = cos A Equation 2
Is there a way to combine these two equations so that we can work with only one variable-either A or B?
One identity to use is Tan p = sin p / cos p.
Can you use the two equations to find Tan B? (Hint: divide the first by the second).
Now that you have your expression for Tan B, you can find an expression in terms of x and y for cos B (or sin B).
Method 1. Use a right triangle (remember tan B = opposite/adjacent) to determine the hypotenuse.
From this triangle, what is the expression for cos B?
Next, what is the expression for x cos B? This is one expression for cos A.
At this point, you can determine cos2 A.
Method 2. Use the identity Tan2B + 1 = sec2B = 1/ cos2B.
From this, you should be able to see that cos2B = 1/(tan2B + 1).
Finally, use equation 2 from above to convert cos2B to cos2A.
Best wishes.
Md. H.
Thanks for the answer However, I found out anothersolution in terms of x and y i.e. x^2 cos^2B = cos^2A ........ (1) y^2sin^2B =cos^2A ........(2) substracting (1) from (2) we get =x^2cos^2B -y^2sin^2 B =0 =x^2cos^2B-y^2(1-cos^2B)=0 =cos^2B (x^2 + y^2)=y^2 =cos^2A/x^2 (x^2 + y^2)= y^2 so, cos^2A =x^2y^2 /(x^2 + y^2) Thanks once agian11/06/21