How many moles of MgS2O3 are in 195 g of the compound? 195 g MgS2O3

Answer 1

Mg = 24.3 g/mol

S = 32.1 g/mol

O = 16 g/mol

Molar mass MgS₂O₃ = 24.3 + (2x32.1) + (3x16) = 24.3 + 64.2 + 48 = 136.5 g/mol

moles MgS₂O₃ = 195 g x 1 mol / 136.5 g = 1.43 moles