Fill in the blank with a number to make the expression a perfect square. v^2-12v+

Answer 1

take half the coefficient of the linear term. -12/2 =-6

square it: (-6)^2 = 36

v^2 -12v +36 is a perfect square = (v-6)^2

(v-6)(v-6) = v^2 -6v -6v + 36 = v^2 -12v +36

Answer 2

v^2-12v+__

First, divide the middle term by 2:

-12/2 = -6

Then, square this value:

(-6)² = 36

The result is v²-12v+36. We know this is a perfect square because it factors to (v-6)².