a wood board 59 inches long is cut into three parts. the first part is twice the length of the second part.

Question

a wood board 59 inches long is cut into three parts. the first part is twice the length of the second part.

Answer 1

F=2S

F+S+ T=59

2S+S +T=59

3S +T= 59

T=59-3S

S=F/2

S=(59-T)/3

F, S, and T all <59

F>S

but T could be larger or smaller than F and S, or

F<T<S

T= 56, F=2, S=1 is possible, T>F>S

T =2, F= 38, S=19 is possible, F>S>T

T = 20, F=26, S=13 is possible, F>T>S

You need more information for a unique solution

and to avoid an infinite number of solutions

the problem as given has 2 equations, 3 unknown variables. You need a 3rd equation to match the number of unknowns.

Answer 2

2nd part is x

1st part is 2x

3rd part is 59-3x