Raymond B. answered 03/18/24
Tutor
5
(2)
Math, microeconomics or criminal justice
(1/(2s+1))*(2/s)
= 2/(2s+1)(s)
= a/(2s+1) + b/s
2 = as + 2bs + b
2 = (a+2b)s + b
let s=0, then b= 2, a=-4
2/(2s+1)s = -4/(2s+1) + 2/s = the partial fractions
=-4s/(2s+1)s +(4s+2)/(2s+1s) = 2/(2s+1)s