How many L of 0.351 M NaOH is needed to completely neutralize 1.25 L of 0.444 M H2SO4 . Make sure your answer has the correct number of significant figures.

Answer 1

2NaOH + H₂SO₄ ==> Na₂SO₄ + 2H₂O ... balanced equation

Note that it takes 2 moles NaOH for each 1 mol H₂SO₄.

mols H2SO4 present = 1.25 L x 0.444 mols/L = 0.555 mols

mols NaOH needed = 0.555 mols H2SO4 x 2 mols NaOH / mol H2SO4 = 1.11 mols NaOH needed

To find the volume, we proceed as follows:

(x L)(0.351 mol/L) = 1.11 mols and x = 3.16 L (3 sig. figs.)