Can someone please help me with this Geometry question?

Question

Question:

A person on top of a 44-meter water tower sees a car below. If the angle of depression between the top of the water tower to the car below is 30°, how far, in meters, is the person from the car?

Answer:

I got 88 meters. Is my answer correct?

Answer 1

It really helps to draw a diagram

if angle of depression is 0 degrees, the car is directly below and is 44 feet away

or does angle of depression have to be 90 degrees for the car to be directly below?

if the angle of depression is 30 degrees, the angle between the tower and line of sight to the car, that would create a right triangle, and the distance from the person to the car would be the hypotenuse of that right triangle

with sides 44 and 44/sq3. hypotenuse= 88/sqr3 = about 50.81 feet

but if by "angle of depression" you mean the angle formed with the ground, then the two sides of the right triangle are 44 and 44sqr3 and the hypotenuse = 88 feet

the car is then 44sqr3 feet from the base of the tower or about 76.2 feet

Odds are your 88 feet answer is what they want for the answer.

otherwise 50.81 feet is Plan B.

Answer 2

That is correct. Because the angle of depression is 30 degrees, the angle of elevation from the car to the top of the tower is 30 degrees. We have a 30-60-90 right triangle. If the side opposite the car is 44, then the distance from the person to the car is twice that because it is opposite the 90 degree angle.