what is the equation of the line through point (-5,5) and perpendicular to y=5/9x-4

Answer 1

(-9/5) is the slope of the perpendicular line.

Slope intercept form is y=mx+b

y=(-9/5)x + b plugging in the point (-5,5)

5 = (-9/5)(-5) + b

5 = 9 + b

b = -4

So perpendicular line equation through the given point is y=(-9/5)x -4

Answer 2

y=-9x/5 + b

5 =-9(-5)/5 + b

5=9+b

b = 5-9 =-4

y= -9x/5 -4 in slope intercept form

or multiply by 5 to remove the fraction

5y=-9x -20

9x +5y =-20 is the perpendicular line through the given point