For mean 84 and SD = 5, z = (x - 84)/5
Transform P(67 < x < 79) to P( (67-84)/5 < z < (79 - 84)/5) = P(-3.4 < z < -1) = P(z < -1) - P(z < -3.4) = 0.1587 - 0.0003 = 0.1584.
Ken W.
asked 07/31/21Assume the random variable x is normally distributed with mean μ=84 and standard deviation σ=5.
Find the indicated probability.
P(67<x<79)
For mean 84 and SD = 5, z = (x - 84)/5
Transform P(67 < x < 79) to P( (67-84)/5 < z < (79 - 84)/5) = P(-3.4 < z < -1) = P(z < -1) - P(z < -3.4) = 0.1587 - 0.0003 = 0.1584.
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