For mean 87 and SD = 5, z = (x - 87)/5
Transform P(72 < x < 83) to P( (72-87)/5 < z < (83 - 87)/5) = P(-3 < z < -0.8) = P(z < -0.8) - P(z < -3) = 0.2119 - 0.0013 = 0.2106.
Ken W.
asked 07/31/21Assume the random variable x is normally distributed with mean μ=87 and standard deviation σ=5.
Find the indicated probability.
P(72<x<83)
For mean 87 and SD = 5, z = (x - 87)/5
Transform P(72 < x < 83) to P( (72-87)/5 < z < (83 - 87)/5) = P(-3 < z < -0.8) = P(z < -0.8) - P(z < -3) = 0.2119 - 0.0013 = 0.2106.
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