Math word problem plz help

Question

Nina loves chocolate milk. She has one bottle of milk that is 60% chocolate and another bottle of milk that is 40% chocolate. How much of each does she need to mix if she wants to have 1000 mL of chocolate milk that is 48% chocolate (her favorite)?

Answer 1

These used to confuse me, too!

Let a = the amount of 60% chocolate milk and let b = the amount of 40% chocolate milk.

a + b = 1000

0.6a + 0.4b = 0.48(1000)

Let's solve the first equation for a.

a = 1000 - b

Suuuubstitute!

0.6(1000 - b) + 0.4b = 0.48(1000)

600 - 0.6b + 0.4b = 480

-0.2b = -120

b = 600 mL

I bet you can find a. Go!

Answer 2

Hello Caleb

Lets say x represents amount of 60% and

1000 - x represents 40% of mixture. (total is 1000ml)

the equation should be

x*60% + (1000- x)*40% = 1000*48% (you can cancel all of the percents by multiplying each by 100)

60x +(1000-x)*40 = 1000*48

60x +40000 - 40x = 48000 (combine x)

20x +40000 = 48 000. (cancel 40000)

20x = 8000. (cancel 20)

x = 400

400ml of 60%; 1000-400 = 600ml of 40%

hope that helps