What is the equation of the line that has a slope of -2 and goes through the point (4, -11)?

Answer 1

Using the general formula of an equation of a line y=mx+b. The m would be the slope, which is -2. When you plug in -2 into the equation you get y=-2x+b. Now plug in the 4 with the x and the -11 with the y. This is because (4,-11) is (x,y). So -11=-2(4)+b. -11=-8+b. b=-3. Now you want the equation to just have the x and y variables. Take the slope-intercept form y=mx+b substitute the m for -2 and the b for -3. Therefore, the equation of the line would be y=-2x-3.

For better view:

y=mx+b

y=-2x+b

(-11)=-2(4)+b

-11=-8+b

b=-3

equation of line: y=-2x-3

Answer 2

Hello Luis

You can use slope-point formula here

y - y₁ = m(x - x₁) where m= -2, (x₁,y_{1) =} (4, -11)

y - -11 = -2(x - 4)

hope that helps