If the concentration of OH- ions is 2.7x10-9 M, what would the pOH be? Question 6 options: 8.57 8.63 9.43 9.36

Question

If the concentration of OH^- ions is 2.7x10^-9 M, what would the pOH be?

Question 6 options:

	8.57
	8.63
	9.43
	9.36

Answer 1

pOH = -log [OH-] = -log 2.7x10^-9

pOH = 8.57 , not 9.36

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