J.R. S. answered 07/26/21
Ph.D. University Professor with 10+ years Tutoring Experience
This following answer provides the calculation for the concentration of Fe2+ in the final solution after all the Fe3+ has been reduced. It does not provide the concentration of Fe2+ in the original sample.
5Fe2+ + MnO4- + 8H+ ==> Mn2+ + 5Fe3+ + 4H2O ... balanced redox equation
mols MnO4- used = 0.0167 L x 0.0813 mol/L = 0.00140 mols MnO4-
mols Fe2+ present = 0.00140 mols MnO4- x 5 mols Fe2+ / mol MnO4- = 0.00680 mols Fe2+
Volume of solution = 10.0 ml x 1 L/1000 ml = 0.0100 L
Concentration of Fe2+ = 0.00680 mols / 0.0100 L = 0.6789 mol/L = 0.679 mol/L
a = 0
b = 6
c= 7
d = 9