please help me. How do I solve this: Given the function f(X) = 5 sin (-2x + 540^o) - 4

Question

1. State the transformations
2. Show your transformation statement and table of values
3. State the domain and range of the function
4. Graph 2 cycles of the functio

Answer 1

Your claim of 540^o is either a 1 or a misprint and you need to fix for a correct solution. Otherwise, Amplitude is 5, The phase shift is found by factoring out the 2 from the term (-2x + 540^o) still weird! There is a vertical shift down of 4. The period of a sin or cos function is ALWAYS 2pi/b Thus, 2pi/2 = pi.

Domain is all reals.

Range is -4 +/- 5 because a sin function oscillates between 1 and -1 from the center line which is -4. So, range is between y = (-9,1)